(4x^4+4x^3+x^2)-3(2x^2+x)+2=0

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Solution for (4x^4+4x^3+x^2)-3(2x^2+x)+2=0 equation: 


Simplifying
(4x4 + 4x3 + x2) + -3(2x2 + x) + 2 = 0

Reorder the terms:
(x2 + 4x3 + 4x4) + -3(2x2 + x) + 2 = 0

Remove parenthesis around (x2 + 4x3 + 4x4)
x2 + 4x3 + 4x4 + -3(2x2 + x) + 2 = 0

Reorder the terms:
x2 + 4x3 + 4x4 + -3(x + 2x2) + 2 = 0
x2 + 4x3 + 4x4 + (x * -3 + 2x2 * -3) + 2 = 0
x2 + 4x3 + 4x4 + (-3x + -6x2) + 2 = 0

Reorder the terms:
2 + -3x + x2 + -6x2 + 4x3 + 4x4 = 0

Combine like terms: x2 + -6x2 = -5x2
2 + -3x + -5x2 + 4x3 + 4x4 = 0

Solving
2 + -3x + -5x2 + 4x3 + 4x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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